x^2+20x-32=0

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Solution for x^2+20x-32=0 equation:


Simplifying
x2 + 20x + -32 = 0

Reorder the terms:
-32 + 20x + x2 = 0

Solving
-32 + 20x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '32' to each side of the equation.
-32 + 20x + 32 + x2 = 0 + 32

Reorder the terms:
-32 + 32 + 20x + x2 = 0 + 32

Combine like terms: -32 + 32 = 0
0 + 20x + x2 = 0 + 32
20x + x2 = 0 + 32

Combine like terms: 0 + 32 = 32
20x + x2 = 32

The x term is 20x.  Take half its coefficient (10).
Square it (100) and add it to both sides.

Add '100' to each side of the equation.
20x + 100 + x2 = 32 + 100

Reorder the terms:
100 + 20x + x2 = 32 + 100

Combine like terms: 32 + 100 = 132
100 + 20x + x2 = 132

Factor a perfect square on the left side:
(x + 10)(x + 10) = 132

Calculate the square root of the right side: 11.489125293

Break this problem into two subproblems by setting 
(x + 10) equal to 11.489125293 and -11.489125293.

Subproblem 1

x + 10 = 11.489125293 Simplifying x + 10 = 11.489125293 Reorder the terms: 10 + x = 11.489125293 Solving 10 + x = 11.489125293 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + x = 11.489125293 + -10 Combine like terms: 10 + -10 = 0 0 + x = 11.489125293 + -10 x = 11.489125293 + -10 Combine like terms: 11.489125293 + -10 = 1.489125293 x = 1.489125293 Simplifying x = 1.489125293

Subproblem 2

x + 10 = -11.489125293 Simplifying x + 10 = -11.489125293 Reorder the terms: 10 + x = -11.489125293 Solving 10 + x = -11.489125293 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + x = -11.489125293 + -10 Combine like terms: 10 + -10 = 0 0 + x = -11.489125293 + -10 x = -11.489125293 + -10 Combine like terms: -11.489125293 + -10 = -21.489125293 x = -21.489125293 Simplifying x = -21.489125293

Solution

The solution to the problem is based on the solutions from the subproblems. x = {1.489125293, -21.489125293}

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